3[2-3(y-2)]=12

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Solution for 3[2-3(y-2)]=12 equation:


Simplifying
3[2 + -3(y + -2)] = 12

Reorder the terms:
3[2 + -3(-2 + y)] = 12
3[2 + (-2 * -3 + y * -3)] = 12
3[2 + (6 + -3y)] = 12

Combine like terms: 2 + 6 = 8
3[8 + -3y] = 12
[8 * 3 + -3y * 3] = 12
[24 + -9y] = 12

Solving
24 + -9y = 12

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-24' to each side of the equation.
24 + -24 + -9y = 12 + -24

Combine like terms: 24 + -24 = 0
0 + -9y = 12 + -24
-9y = 12 + -24

Combine like terms: 12 + -24 = -12
-9y = -12

Divide each side by '-9'.
y = 1.333333333

Simplifying
y = 1.333333333

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